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Minimum Gifts | TCS CodeVita 9 Solution ( Zone 1 ) 2020 | By CodingHumans |

3
Minimum Gifts

Problem Description

A Company has decided to give some gifts to all of its employees. For that, company has given some rank to each employee. Based on that rank, company has made certain rules to distribute the gifts.

The rules for distributing the gifts are:

Each employee must receive at least one gift.

Employees having higher ranking get a greater number of gifts than their neighbours.

What is the minimum number of gifts required by company?

Constraints

1 < T < 10

1 < N < 100000

1 < Rank < 10^9

Input

First line contains integer T, denoting the number of testcases.

For each testcases:

First line contains integer N, denoting number of employees.

Second line contains N space separated integers, denoting the rank of each employee.

Output

For each testcase print the number of minimum gifts required on new line.

Time Limit

1

Examples
Example 1

Input

2
5
1 2 1 5 2
2
1 2

Output

7
3

Explanation

For testcase 1, adhering to rules mentioned above,

Employee # 1 whose rank is 1 gets one gift

Employee # 2 whose rank is 2 gets two gifts

Employee # 3 whose rank is 1 gets one gift

Employee # 4 whose rank is 5 gets two gifts

Employee # 5 whose rank is 2 gets one gift

Therefore, total gifts required is 1 + 2 + 1 + 2 + 1 = 7

Similarly, for testcase 2, adhering to rules mentioned above,

Employee # 1 whose rank is 1 gets one gift

Employee # 2 whose rank is 2 gets two gifts

Therefore, total gifts required is 1 + 2 = 3




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Solution
( C ++ )





If you have any doubts regarding this problem or  need the solution in other programming languages then leave a comment down below . 

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3 Comments
  1. can we get a python solution pleaseee

    ReplyDelete
  2. need solution in java language

    ReplyDelete
    Replies
    1. convert this c++ logic will be same
      #include
      using namespace std;
      int mingifts (vector &ratings) {
      int gifts = 0;
      int size = ratings.size();

      // if the vector is empty: return zero
      if (size == 0) return gifts;

      int giftState = 1;
      for (int i = 0; i < size; i++)
      {
      if (i == size - 1)
      {
      gifts += giftState;
      continue;
      }

      if (ratings[i + 1] > ratings[i])
      {
      gifts += giftState;
      giftState++;
      }
      else if (ratings[i + 1] < ratings[i])
      {
      int startgiftState = giftState;
      int startIndex = i;

      while (i + 1 < size && ratings[i + 1] < ratings[i])
      {
      i++;
      }

      int startgiftStateFromRight = i - startIndex + 1;
      gifts += (startgiftStateFromRight + 1) * startgiftStateFromRight / 2;

      // Adjusting for the local maxima point.
      if (startgiftState > startgiftStateFromRight)
      {
      gifts += startgiftState - startgiftStateFromRight;
      }

      // Let's exclude this local minima point now as this will be accounted in the next iteration.
      gifts--;
      i--;
      giftState = 1;
      }
      else
      {
      gifts += giftState;
      giftState = 1;
      }
      }

      // return the miimum gifts required the the given ratings vector
      return gifts;
      }

      //driver code
      int main()
      {
      int t;
      cin>>t;
      while(t--)
      {
      long n,l;
      cin>>n;
      vector rating; // vector of ratings

      for(int i=0;i>l;
      rating.push_back(l);
      }

      //print the output, mingifts function return the minimum gifts required
      cout<<mingifts(rating)<<endl;
      }
      return 0;
      }

      Delete
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