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Count Pairs | TCS CodeVita 9 Solution ( Zone 1 ) 2020 | By CodingHumans |

CodingHumans 11 August 3


Count Pairs

 Problem Description

 Given an array of integers A, and an integer K find number of happy elements.

Element X is happy if there exists at least 1 element whose difference is less than K i.e. an element X is happy,
 if there is another element in the range [X-K, X+K] other than X itself.

Constraints

1 <= N <= 10^5

0 <= K <= 10^5

0 <= A[i] <= 10^9

Input

First line contains two integers N and K where N is size of the array and K is a number as described above

Second line contains N integers separated by space.


Output

 Print a single integer denoting the total number of happy elements.

Time Limit

1

Examples
Example 1

 Input

6 3
5 5 7 9 15 2

Output

5

Explanation

Other than number 15, everyone has at least 1 element in the range [X-3, X+3].
 Hence they are all happy elements. Since these five are in number, the output is 5.

Example 2

 Input

3 2
1 3 5

 Output

3

Explanation

All numbers have at least 1 element in the range [X-2, X+2]. Hence they are all happy elements.
Since these three are in number, the output is 3.



Recommended: Please try your approach on your integrated development environment (IDE) first, before moving on to the solution.

Few words from CodingHumans : Don't Just copy paste the solution, try to analyze the problem and solve it without looking by taking the the solution as a hint or a reference . Your understanding of the solution matters.


HAPPY CODING 😁



Solution 
( C ++ )


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3 Comments
  1. Aditya Sadaphule12 August 2020 at 12:03

    can you send the same code in python
    and does the ques is like from ex 1 for 5 the range [5-3=2,5+3=8] and 7 and 2 is in this range is this a proper approach

    ReplyDelete
  2. Unknown14 August 2020 at 00:49

    This solution works fine😊

    ReplyDelete
  3. Unknown12 September 2020 at 21:01

    import java.util.*;
    class B{
    public static void main(String ar[])
    {
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    int k = sc.nextInt();
    int count=0,i;
    int arr[] = new int[n];
    B b = new B();
    for(i=0;i=l) && (ar[j]<= h))
    {
    return 1;
    }
    }
    }
    return 0;
    }
    }

    ReplyDelete

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